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A given network is 172.16.0.0/18. Design 4 subnets for 500, 250, 700, 1000 hosts. Find subnetmask, networkID, broadcastID and IP ranges for each subnets and hence find the supernet parameter as well.

start with the subnet for 1000 hosts. To accommodate 1000 hosts, we need to find the smallest subnet size that can accommodate at least 1000 hosts. Since 2^10 = 1024, we need at least 10 host bits.

Given that the original network is 172.16.0.0/18, we have 18 network bits and 14 host bits. To create a subnet with 10 host bits, we'll borrow 2 more bits from the host portion, making it a /20 subnet (18 network bits + 2 subnet bits + 10 host bits).

Here are the details for the subnet with 1000 hosts:

Subnet mask: /20 (255.255.240.0) Network ID: 172.16.0.0 Broadcast ID: 172.16.15.255 Usable IP range: 172.16.0.1 to 172.16.15.254

Next, let's proceed with the subnet for 700 hosts. We already used 4 bits for the previous subnet (/20), so we need to borrow 3 more bits to accommodate 700 hosts. This gives us a /23 subnet (18 network bits + 3 subnet bits + 7 host bits).

Here are the details for the subnet with 700 hosts:

Subnet mask: /23 (255.255.254.0) Network ID: 172.16.16.0 Broadcast ID: 172.16.17.255 Usable IP range: 172.16.16.1 to 172.16.17.254

Moving on to the subnet for 500 hosts, we've already used 7 bits for the previous subnets (/20 and /23), so we need to borrow 2 more bits to accommodate 500 hosts. This gives us a /22 subnet (18 network bits + 2 subnet bits + 8 host bits).

Here are the details for the subnet with 500 hosts:

Subnet mask: /22 (255.255.252.0) Network ID: 172.16.20.0 Broadcast ID: 172.16.23.255 Usable IP range: 172.16.20.1 to 172.16.23.254

Lastly, for the subnet with 250 hosts, we've already used 9 bits for the previous subnets (/20, /23, and /22), so we need to borrow 1 more bit to accommodate 250 hosts. This gives us a /21 subnet (18 network bits + 1 subnet bit + 9 host bits).

Here are the details for the subnet with 250 hosts:

Subnet mask: /21 (255.255.248.0) Network ID: 172.16.24.0 Broadcast ID: 172.16.31.255 Usable IP range: 172.16.24.1 to 172.16.31.254

Now, let's find the supernet parameters:

The smallest supernet that encompasses all these subnets would have the network address 172.16.0.0/18, as it includes all the individual subnets within it. So, the supernet parameters are:

Supernet mask: /18 (255.255.192.0) Network ID: 172.16.0.0 Broadcast ID: 172.16.63.255 Usable IP range: 172.16.0.1 to 172.16.63.254

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